- Ideal Gas: A Gas that obeys PV=nRT at all values of temperature, pressure and volume.
The Assumptions of Ideal Gas
- It contains the same type of molecules.
- All collisions with the wall of container are elastic.
- Kinetic energy of the atoms are directly proportional to the temperature.
- There are no inter-molecular forces of attraction, subsequently, there is no potential energy among the atoms.
- At 0 Kelvin the mean kinetic energy becomes 0.
Proofs
- Show that PV=NKT
we also know that n=N/Na
so PV=NRT
now since K=R/Na
PV=NKT
- Pressure of a single atom along the x-axis
Suppose there is a cube shaped container with length L that has a single atom of ideal gas and the atom has speed v:
ΔP = mv - (-mv)
ΔP=2mv
F= ΔP/Δ T =2mv/t
since the collision is elastic T=2L/V
Now putting equation (2) in (1) we get mv2 /L3
Now since Pressure = Force/Area
Pressure = mv2/L3
- Total Pressure
PN=mv2N/l3
Total Pressure:
P=P1+P2..... PN
mv21/L3+mv22/L3+mv2N/L3
m/L3 (v21+v22+v2N)
Now since the mean square speed is denoted by
<v2> = v21+v22+v2N / N
Plugging the above mentioned expression in the expression of total Pressure:
P=Nm<v2> /L3
- Total pressure for N atoms
<c2> = <v2x>+<v2y>+ <v2z>
since it is an ideal gas so <v2x> = <v2y> = <v2z>
<c2> = 3 <v2>
1/3<c2> = <v2>
Plugging this in the expression of Total Pressure
P=1/3 Nm<c2>/L3
- Mean Kinetic Energy of an atom of ideal gas:
PV=NKT
PV=1/3Nm<c2>
3KT=m<c2>
multiplying both sides with 1/2
3/2KT = Kinetic Energy
Brownian Motion
- It is the random motion of microscopic particles in a fluid as a result of countinuous bombardment from molecules of the surrounding medium
The following is observed:
- Bright tiny Smoke particles are jerking sideways in a random motion
- Particles randomly moved into and out of focus of the microscope, It indicates random vertical motion of the particles